
Bobosharif S. answered 08/11/23
PhD in Math, MS's in Calulus
∫(4x2+3)2dx
= ∫(16x4+24x2 +9) dx = (16/5)x5 +(24/3)x3+9x+Constant
= (16/5)x5 +(8)x3+9x+Constant
Now take derivative of
( (16/5)x5 +(8)x3+9x+Constant))' = = 16x4 +24x2+9 which is the same as the expression under the integral.