Mark M. answered 08/10/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
PV1.4 = C
V1.4(dP/dt) + 1.4V-3/4(dV/dt)P = 0
dV/dt = -V(dP/dt) / [1.4P]
dV/dt = -310(-14) / [1.4(81)]
Morgen P.
asked 08/10/23When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4=C where C is a constant. Suppose that at a certain instant the volume is 310 cubic centimeters and the pressure is 81 kPa and is decreasing at a rate of 14 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant
Mark M. answered 08/10/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
PV1.4 = C
V1.4(dP/dt) + 1.4V-3/4(dV/dt)P = 0
dV/dt = -V(dP/dt) / [1.4P]
dV/dt = -310(-14) / [1.4(81)]
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