At what point(s) on the curve x = 6t2 + 2, y = t3 − 8 does the tangent line have slope 1 2 ? (x, y) =

Answer 1

x = 6t² + 2 and y = t³ - 8

slope of tangent = dy/dx = (dy/dt) / (dx/dt) = 3r² / (12t) = t/4 = 12

Solve for t and then find x and y.

Answer 2