Raymond B. answered 08/03/23
Math, microeconomics or criminal justice
F(x) = (2x^3+3x^2 -5)(5x^2 -2x +1)
F(x) = 2x^3 +3x^2 -5 + 10x^5 + 15x^4-25x^2 -4x^4 -6x^3 +10x
= 10x^5 +11x^4 -4x^3 -22x^2 +10x -5
F'(x) = 50x^4 + 44x^3 -12x^2 -44x +10
Constance V.
asked 08/02/23F(x)= (2x3+3x2-5)(5x2-2x+1)
Raymond B. answered 08/03/23
Math, microeconomics or criminal justice
F(x) = (2x^3+3x^2 -5)(5x^2 -2x +1)
F(x) = 2x^3 +3x^2 -5 + 10x^5 + 15x^4-25x^2 -4x^4 -6x^3 +10x
= 10x^5 +11x^4 -4x^3 -22x^2 +10x -5
F'(x) = 50x^4 + 44x^3 -12x^2 -44x +10
Use the product rule (and power rule (xn)' = nxn-1) to find F'(x):
F'(x) = (2x3 + 3x2 - 5)' • (5x2 - 2x + 1) + (2x3 + 3x2 - 5) • (5x2 - 2x + 1)'
........= (6x2 + 6x)(5x2 - 2x + 1) + (2x3 + 3x2 - 5)(10x - 2)
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