Let f(x)=x^3-3x^2+20x-268

Question

A solution to f(x)=0 can be found in the interval <x<

(Enter a pair of consecutive integers m, M where a solution is guaranteed to exist in the interval m<x<M).

If you draw the line tangent to the graph of y=f(x) through the point where x is the LOWER of the two x-values, this line will have equation y=

This suggests a solution to f(x)=0 is x≈   (round your answer to four decimal places)

Answer 1

m<x<M

6<x<7

just graph the polynomial and see where it intersects the x axis, a little more than 6