Yefim S. answered 07/30/23
Math Tutor with Experience
xn+1 = xn - f(xn)/f'(xn), n = 1, 2, 3, ...
f'(x) = 12x2 + 8; x1 = - 1; x2 = - 0.45; x3 = - 0.1657718
Renata A.
asked 07/30/234x^3+8x+1=0 as follows.
Let x1=-1 be the initial approximation.
The second approximation x2 is:
and the third approximation x3 is:
Yefim S. answered 07/30/23
Math Tutor with Experience
xn+1 = xn - f(xn)/f'(xn), n = 1, 2, 3, ...
f'(x) = 12x2 + 8; x1 = - 1; x2 = - 0.45; x3 = - 0.1657718
Doug C. answered 07/30/23
Math Tutor with Reputation to make difficult concepts understandable
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