Mark M. answered 07/29/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x = distance travelled by the eastbound walker in t hours
Let y = distance travelled by the northeastbound walker in t hours
Let z = distance between the walkers in t hours
By the Law of Cosines, z2 = x2 + y2 - 2xycos45°
So, z2 = x2 + y2 - √2 xy
2z(dz/dt) = 2x(dx/dt) + 2y(dy/dt) - √2 [ x(dy/dt) + y(dx/dt) ]
When t = 15 min = 1/4 hr, x = 3/4 mi and y = 5/4 mi
dx/dt = 3 amd dy/dt = 5
Find z and then solve for dz/dt.
Seung hyun H.
Thank you07/29/23