Patrick F. answered • 07/22/23
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LIAN Q.
asked • 07/22/23definite integral b= 2 a = 0 x(x-3)dx
evaluate the integral
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AJ L. answered • 07/22/23
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∫02 x(x-3)dx
= ∫02 (x2-3x)dx
= x3/3 - (3/2)x2 [0,2]
= [23/3 - (3/2)(2)2] - [03/3 - (3/2)(0)2]
= [8/3 - (3/2)(4)] - 0
= 8/3 - 6
= 8/3 - 18/3
= -10/3
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