For Each function determine the critical values. no decimal answers. y=4^x e^(2x^2)

Question

Answer 1

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ln(y)=x*ln4+2x²

y'/y=ln4+4x

y'=(ln4+4x)*(4^x*2e^{2x^2)}

the second term in parenthesis is always>0

so y'=0 when x=[ln(.25)]/4

Answer 2

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