
Laurel D. answered 07/21/23
Mathematics PhD student with experience in MATLAB, ML, and more
a) This one, I would say, try this out! Set up the equation for eigenvector x associated with eigenvalue λ:
y = Ak x
Then, go through one by one converting (Ax) -> (λx) (since we can always rearrange (Aλx) -> (λAx) since λ is scalar). What is y? If it's (λkx) you have your answer. But be careful, because if λk is not an eigenvalue here, that does not disprove the statement.
b/c) Try to think of counterexamples for both of these. I can help more if necessary. (b) might require a little more thought, but (c) you only need a zero on the diagonal of D for A = PDP-1 to make things complicated for invertibility. Try it out! You only need a 2x2 matrix to prove either.