Find the equation of the line through point (3,−3) and parallel to y=3x−4 .

Answer 1

If it's parallel to y = 3x - 4, then the slope will also be 3 (y = mx + b, where x is slope and b is y-int).

To go through (3, -3), need find a new "b".

-3 = 3(3) + b

b = -12.

y = 3x - 12

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Answer 2

Follow the solution provided by William W.