
Yefim S. answered 06/29/23
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v = π∫0π/10[cos(5x) + 3)2 - 32]dx = π∫0π/10{cos2(5x) + 6cos(5x)}dx = π[ x/2 + sin(10x)/20 + 6sin(5x)/5]0π/10= π(π/20 + 6/5)
Michael F.
asked 06/28/23Yefim S. answered 06/29/23
Math Tutor with Experience
v = π∫0π/10[cos(5x) + 3)2 - 32]dx = π∫0π/10{cos2(5x) + 6cos(5x)}dx = π[ x/2 + sin(10x)/20 + 6sin(5x)/5]0π/10= π(π/20 + 6/5)
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