
Yefim S. answered 06/28/23
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v = 2π∫02x·x2dx = πx4/202 = 8π
Michael F.
asked 06/28/23Yefim S. answered 06/28/23
Math Tutor with Experience
v = 2π∫02x·x2dx = πx4/202 = 8π
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