Xenia M. answered 07/11/24
Calculus Tutor with Advanced Math BS Expertise
Terms:
- Continuous Compounding: Interest is calculated and added to the account balance continuously.
- Future Value = FV = The amount of money an investment will grow to over time with continuous compounding.
FV = ∫(from 0 to T) R(t)⋅er(T-t)dt
Where:
- T is the total time period (4 years)
- R(t) is the income stream rate (120,000 dollars/year)
- r is the continuous compounding interest rate (3.5% or 0.035)
Steps to Solve:
- Set Up the Integral: FV = ∫[from 0 to 4] 120,000⋅e^0.035(4−t) dt
- Evaluate and simplify the Exponent: FV=120,000 ∫[from 0 to 4] e^(0.14−0.035t) dt
- Change of Variables:
Let u = 0.14 − 0.035t
du=−0.035 dt
Adjust the limits of integration:
- When t=0, u=0.14
- When t=4, u=0
FV=120,000 ∫[from 0 to 0.140] e^u⋅(du/−0.035)
- Integrate, with your final result should be: FV = −120K/0.035*(1−e^0.14)
- Calculate the Values:
e^0.14 ≈ 1.15027
FV = −120,000/0.035 * (1−1.15027)
FV ≈ 515,211.43 - Final answer.