Inactive Tutor answered 06/24/23
Tutor
New to Wyzant
r = 10(1 + cosθ); Area A = 2·1/2∫0π100(1 + cosθ)2dθ = 100∫0π(1 + 2cosθ + cos2θ)dθ = 100(θ + 2sinθ + 1/2θ +
1/4sin2θ)0π = 100(3/2π) = 150π
Dayvon B.
asked 06/24/23Find the area enclosed by the curve r= 10(1+cos(theta)).
Inactive Tutor answered 06/24/23
r = 10(1 + cosθ); Area A = 2·1/2∫0π100(1 + cosθ)2dθ = 100∫0π(1 + 2cosθ + cos2θ)dθ = 100(θ + 2sinθ + 1/2θ +
1/4sin2θ)0π = 100(3/2π) = 150π
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