
Yefim S. answered 06/24/23
Math Tutor with Experience
Let x is side of bottom and y is height of box Then x2y = 320. Then cost function C(c,y) = 15x2 + 10x2 + 10xy = 25x2 + 10xy; y = 320/x2. Then C(x) = 25x2 + 3200/x; C'(x) = 50x - 3200/x2 = 0; 50x3 - 3200 = 0; x3 = 64;
x = 4 feet. C''(x) = 50 + 6400/x3; C''(4) = 50 + 100 = 150 > 0. So, we have minimum
x = 4 feet; y = 320/16 = 20 feet