
Yefim S. answered 06/23/23
Math Tutor with Experience
Area A = 1/2∫02π(xdy/dθ - ydx/dθ)dθ = 1/2∫02π(12cosθ·18cosθ + 18sinθ·12sinθ)dθ = 108·2π = 216π
Dayvon B.
asked 06/23/23Use the parametric equations of an ellipse
x = 12cos(theta)
y = 18sin(theta)
0 ≤ (theta) ≤ 2pi
to find the area that it encloses.
Yefim S. answered 06/23/23
Math Tutor with Experience
Area A = 1/2∫02π(xdy/dθ - ydx/dθ)dθ = 1/2∫02π(12cosθ·18cosθ + 18sinθ·12sinθ)dθ = 108·2π = 216π
Mark M. answered 06/23/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
cosθ = x/12 and sinθ = y/18
Since cos2θ + sin2θ = 1, we have x2 / 122 + y2 / 182 = 1
a = 18 and b = 12
Area = πab = 216π
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