
Yefim S. answered 02/04/24
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dy = y'(x)dx; dy = y'(10)dx; y'(x) = - 1/x2; y'(10) = - 1/100; dx = Δx = - 0.003. So, dy = - 1/100·(- 0.003) = 3·10-5
Dawn H.
asked 06/22/23find dy for the given values of x and delta(x) y=1/x, x = 10 delta(x) -0.003
Yefim S. answered 02/04/24
Math Tutor with Experience
dy = y'(x)dx; dy = y'(10)dx; y'(x) = - 1/x2; y'(10) = - 1/100; dx = Δx = - 0.003. So, dy = - 1/100·(- 0.003) = 3·10-5
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