Inactive Tutor answered • 06/19/23
Tutor
New to Wyzant
Solving for eigenvalue.
A-λI=0
(λ+2)(λ+7)+4k = 0
λ2+9λ+14+4k =0
λ=(-9 ± √(81-4(14+4k)))/2=2
when k=0, λ=2
Al G.
asked • 06/19/23Calculus eigenvalue
For which value of k does the matrix A = [−2 k] [−4−7] have one real eigenvalue of algebraic multiplicity 2?
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