Calculus eigenvalue

Question

Let A = [3 -3] For A to have 0 as an eigenvalue, k must be =

[1, k]

Answer 1

The equation you need is det | 3-λ -3|

| 1 k-λ| = 0.

Solve for λ in terms of k and then figure out what value k must have so that λ=0.