AJ L. answered 06/16/23
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Recall that 1/(1-x) = ∑[n=0,∞] xn, thus, the partial sum of the first 5 nonzero terms of 1/(1-x3) are:
1/(1-x3) = ∑[n=0,∞] x3n = 1 + x3 + x6 + x9 + x12
By the ratio test:
limn->∞ |an+1/an|
= limn->∞ |x3n+1/x3n|
= limn->∞ |x|
= |x|
Now set L< 1 to find the radius of convergence:
|x| < 1
-1 < x < 1
-1 < x ≤ 1 <-- Interval of Convergence
Therefore, the radius of convergence is 1.