
Yefim S. answered 06/14/23
Math Tutor with Experience
x2 = ax; x = 0 or x = a > 0
Area A = ∫0a(ax - x2)dx = (ax2/2 - x3/3)0a = a3/2 - a3/3 = a3/6
Alecia S.
asked 06/14/23Find the area between the curves
f(x)=x2
and g(x) = ax. (Assume a > 0)
(Hint: Your answer will be in terms of a.)
The area is
enter your response here.
Yefim S. answered 06/14/23
Math Tutor with Experience
x2 = ax; x = 0 or x = a > 0
Area A = ∫0a(ax - x2)dx = (ax2/2 - x3/3)0a = a3/2 - a3/3 = a3/6
Doug C. answered 06/14/23
Math Tutor with Reputation to make difficult concepts understandable
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