Since we have two times that are k hours after the time of death, we can simply create two equations and solve for r and k. For these equations, we'll use the Newton's law of cooling formula: f(t) = (98.6-65)e-rt + 65.
(a1) f(k) = 91.8 = 33.6e-rk + 65
(b1) f(k+2) = 87.9 = 33.6e-r(k+2) + 65
Solving for these, we get
(a2) rk = ln(33.6/26.8)
(b2) rk + 2r = ln(33.6/22.9)
So r = [ln(26.8) - ln(22.9)]/2 = 0.0786325
Plugging this into equation (a2), we get k = ≈ln(33.6/26.8)/0.0786325 ≈ 2.88.
Thus, the time of death was about 2.88 hours prior (or about 9:07:27.44 AM).