Physics homework question

Question

Question: The edges of a shoebox are measured to be 12.3 cm, 18.8 cm, and 29 cm. ***Determine the volume of the box retaining the proper number of significant figures in your answer.)

Answer 1

Answer 2

12.3 x 18.8 x 29 = 6705.96

= 6706.0 cm^3

= 6706 cm^3 = volume

use a calculator

rough check by rounding more

12x20x30 = 7200, close enough given the rounding

or use the rule of 9's

1+2+3 = 6

1+8+8= 17, 1+7 = 8

2+9 = 11, 1+1 = 2

6x8x2 = 96, 9+6=15, 1+5=6

6+7+0+5 + 9+6 = 33, 3+3 =6

the calculator or long hand arithmetic addition looks about right

12.3 = 12 3/10 = 123/10

18.8 = 18 8/10 = 18 4/5 = 94/5

(123/10)(94/5)(29) = 123/5)(47/5)(29) = 167649/25= 6705.96 = 6705 96/100= 6705 24/25 cm^2

go with 6706 cm^2, as 29 has no decimals, and it may have been rounded to nearest integer

the answer shouldn't have more decimal places than the problem

Volume = length times width times height for a 3D rectangular shaped object

V=Lwh = 18.8x12.3x29

Volume is 3 dimensions. You could graph it in an xyz coordinate system, then calculate a double integral to find volume

Answer 3

V = (12.3)(18.8)(29) cm³