(a) Ω = { (a, b, c, d), a, b, c, d ∈ {1, 2, 3, 4, 5, 6} }
P(ω) = (1/6)4, for all ω ∈ Ω
(b) P(zero 5's) = 4choose0 ×(5/6)4 = (5/6)4
P(only one 5) = 4choose1 × (1/6)(5/6)3 = 4 × (1/6)(5/6)3
P(A) = 1 - (P(zero 5's) + P(only one 5))
P(B) = P(zero 5's) + P(only one 5)
(c) A υ B = Ω because A and B are complements of each other. So P(A) + P(B) = 1