Yefim S. answered 05/16/23
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f'(x) - 3x2[f(x)]3 - 3x3[f(x)]2f'(x) = - 5; at x = 1 we have: f'(1) - 3·12·23 - 3·22·13 ·f'(1) = - 5; - 11f'(1) = 19;
f'(1) = - 19/11