finding f'(1/4)

Question

let f(x) = (arcsin(√x))² find f'(1/4)

Answer 1

f'(x) = (arcsin(√x))' • 2arcsin(√x) = arcsin(√x)/[√(x-x²)]

So, f'(1/4) =arcsin(√(1/4))/[√((1/4)-(1/4)²)] = (π/6)/[√(3/16)]

Hope this helped!