
Bradford T. answered 05/16/23
Retired Engineer / Upper level math instructor
Sm(t)=at2+bt+4
Vm(t)=2at+b
Am(t)=2a
Sn(t)=t3-9t2+ct+d
Vn(t)=3t2-18t+c
An(t)=6t-18
When t=1, Sm= Sn
a+b+4=1-9+c+d --> a+b-c-d = -12
When t = 2, Vn = 0
12-36+c=0 --> c = 24
When t = 0, Am=An
2a=-18 -->a=-9
When t=3, Vm=0
6a+b=0 --> b=-6a = -6(-9) = 54
a+b-c-d=-12
-9+54+24-d=-12
-d=-12+9-54-24=-81
d=81
a=-9
b=54
c=24
d=81