Osama A. answered 05/16/23
Young engineer, experienced in online tutoring
find x and y components, then add all x components, and all y components together,
Step 1: Resolve the forces into their horizontal (x-axis) and vertical (y-axis) components.
Let's assume Josh's force is F₁, Nick's force is F₂, and Mitchell's force is F₃.
For Josh's force: Fx₁ = F₁ * cos(0°) = 608 N * cos(0°) = 608 N Fy₁ = F₁ * sin(0°) = 608 N * sin(0°) = 0 N
For Nick's force: Fx₂ = F₂ * cos(120°) = 550 N * cos(120°) = -275 N Fy₂ = F₂ * sin(120°) = 550 N * sin(120°) = 475 N
For Mitchell's force: Fx₃ = F₃ * cos(150°) = 700 N * cos(150°) = -350 N Fy₃ = F₃ * sin(150°) = 700 N * sin(150°) = 350 N
Step 2: Sum the horizontal and vertical components of the forces to find the resultant components.
Summing the horizontal components: ΣFx = Fx₁ + Fx₂ + Fx₃ = 608 N + (-275 N) + (-350 N) = -17 N
Summing the vertical components: ΣFy = Fy₁ + Fy₂ + Fy₃ = 0 N + 475 N + 350 N = 825 N
Step 3: Find the magnitude of the resultant force using the Pythagorean theorem.
Magnitude of the resultant force: |ΣF| = sqrt((ΣFx)² + (ΣFy)²) = sqrt((-17 N)² + (825 N)²) ≈ 826 N
The magnitude of the resultant force is approximately 826 N.
b) To determine the direction of the resultant force relative to one of the forces, we can use trigonometry. Let's choose Josh's force as a reference.
The angle between the resultant force and Josh's force can be found using the inverse tangent (arctan) function:
θ = arctan(ΣFy / ΣFx) = arctan(825 N / -17 N) ≈ -86.6°
Therefore, the direction of the resultant force, relative to Josh's force, is approximately -86.6°.