Michael D. answered 05/14/23
PhD in Math with 20+ Years Teaching Experience at the University Level
Since a, b, and c behave as free variables, we have:
(a − b, b − c, c − a) = a(1,0,-1) + b(-1,1,0) + c(0,1,-1)
which you can verify directly. Hence the given set is equal to Span(v1, v2, v3) where:
- v1= (1,0,-1)
- v2 = (-1,1,0)
- v3 = (0,1,-1)
The Span of any set of vectors is always a subspace; the proof uses the standard subspace test (show that Span contains the zero vector and is closed under vector addition and scalar multiplication). The notation is a bit inconvenient, but you can find the general proof in most intro Linear Algebra books.