Differentiate the following

Question

𝑦=sqrt 4+3𝑥

Answer 1

Assuming you mean y = √(4+3x):

y = √(4+3x)

dy/dx = (4+3x)' • 1/[2√(4+3x)] <-- Use Chain Rule

dy/dx = 3/[2√(4+3x)]

Hope this helped!

Answer 2

Chain rule: derivative inside * derivative outside

Derivative inside = d/dx 4 + 3x = 3

Derivative outside = cal 4+3x u. Derivative u^1/2 = (1/2)u^(-1/2) = 1/2sqrt(4+3x)

inside * outside = 3/2sqrt(4+3x)