
William W. answered 05/02/23
Experienced Tutor and Retired Engineer
If f(x) = 3√x the at x = 8, f(8) = 3√8 = 6√2 so the point on the curve for which we are "linearizing" the function is (8, 6√2). If we are creating a line at that point, we now need the slope. To get the slope, we use the derivative:
f(x) = 3√x
f(x) = 3(x)1/2
f '(x) = (3/2)(x)-1/2 (using the power rule)
f '(8) = (3/2)(8)-1/2 = 3/(2√8) = 3/(4√2) = (3√2)/8
Using the point-slope form of a line:
y - 6√2 = [(3√2)/8](x - 8)
y = [(3√2)/8]x - 3√2 + 6√2
y = [(3√2)/8]x + 3√2
L(x) = [(3√2)/8]x + 3√2
To estimate f(10):
L(10) = [(3√2)/8]10 + 3√2 = (15√2)/4 + 3√2 = (15√2)/4 + 12√2/4 = (27√2)/4 which is approx 9.55