Raymond B. answered 05/01/23
Math, microeconomics or criminal justice
P(t)=2560e^.017185t from t=0 to 50
P(0)=2,560 million in the year 1950
P(50)= 2560e^.017185(50)=6,045.156 million in the year 2000
= about 6 billion
average population is a little < arithmetic average, given upward concavity of the exponential curve
< (6045.156+2560)/2=8605.156/2
< 4,302.578
helps to sketch a graph
find area under the curve = integral of 2560e^.017185t= (2560/.017185)e^.017185t
evaluated from 0 to 50, then divide by base=50 = average height
= [(2560/.017185)e^.017185(50) -2560/.017185]/50
= 4,056.04 million = average population from 1950 to 2000