I need help please

Question

let f(x)=1/(x+3)

use the limit definition of the derivative to find:

f '(-7)=

f '(-5)=

f '(-2)=

f '(0)=

I mostly have a hard time with "building" the function I just don't understand it

Answer 1

Answer 2

f(x)=1/(x+1)

f'(x)=-1/(x+1)^2

f'(-7)=-1/36

f'(-5)=-1/16

f'(-2)= -1

f(0)= -1

quotient difference = [f(x+h)-f(x)]/h

= [(1/(x+h+3) - (1/x+3)]/h

= -h/h(x+3)(x+h+3)=-1/(x+3)(x+h+3)

limit as h approaches zero

= -1/(x+3)^2