Not sure why this is wrong

Question

Given f"(x)= 1x + 0 , and f'(0) = -5 and f(0) = -4.

find f(x)

and find f(1)

for f(x) I got x^2/-3

and for f(1) I got -(53/6)

Answer 1

Given f"(x)= 1x + 0 , and f'(0) = -5 and f(0) = -4:

f"(x) = 1x + 0

f''(x) = x

f'(x) = x²/2 + C

f'(0) = 0²/2 + C

-5 = C

f'(x) = x²/2 - 5

f(x) = x³/6 - 5x + C

f(0) = 0³/6 - 5(0) + C

-4 = C

f(x) = x³/6 - 5x - 4

f(1) = 1³/6 - 5(1) - 4

f(1) = 1/6 - 5 - 4

f(1) = 1/6 - 30/6 - 24/6

f(1) = -53/6

Seems like you got f(1) right, but f(x) you didn't.

Hope this helped!

Answer 2