
William W. answered 04/19/23
Experienced Tutor and Retired Engineer
Part a)
M(t) = M0ekt
Plug in M = 25, M0 = 100, t = 10
25 = 100e10k
0.25 = e10k
ln(0.25) = ln(e10k)
ln(0.25) = (10k)ln(e)
-1.386294 = 10k
k = -0.1386294
So M(t) = 100e-0.1386294t
Part b)
M(t) = 100e-0.1386294t
10 = 100e-0.1386294t
0.1 = e-0.1386294t
ln(0.1) = ln(e-0.1386294t)
ln(0.1) = (-0.1386294t)ln(e)
-2.302585 = -0.1386294t
t = 16.6096 days
t = 16 days + 0.6096 days
t = 16 days + 0.6096(24) hours
t = 16 days + 14.63 hours
t = 16 days, and 15 hours (rounding to the nearest hour)
Part c)
"How fast the substance is decaying" infers a rate. To get the rate, take the derivative:
M(t) = 100e-0.1386294t
M' = 100(-0.1386294)e-0.1386294t
M' = -13.86294e-0.1386294t
at 2 weeks, t = 14 days
M' = -13.86294e-0.1386294•14
M' = -13.86294e-1.940812
M' = -13.86294(0.1435873)
M' = -1.99 grams/day