Yefim S. answered 12/02/24
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an = n1/4/(n4 + n2)1/3 < n1/4/n4/3 = 1/n13/12; p = 13/12 > 1. So, given series converges
Ellie H.
asked 04/18/23compare the sum n = 1 to ∞ (root(n, 4))/(root(n ^ 4 + n ^ 2, 3)) to the p-series what does p =?
Yefim S. answered 12/02/24
Math Tutor with Experience
an = n1/4/(n4 + n2)1/3 < n1/4/n4/3 = 1/n13/12; p = 13/12 > 1. So, given series converges
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