To find fx(8, 6) and fy(8, 6), we need to take the partial derivatives of f(x, y) with respect to x and y, respectively, and then evaluate them at (8, 6).
So, we have:
fx(x, y) = d/dx [16 − 4x^2 − y^2] = -8x
fy(x, y) = d/dy [16 − 4x^2 − y^2] = -2y
Therefore,
fx(8, 6) = -8(8) = -64 fy(8, 6) = -2(6) = -12
Interpretation:
The value of fx(8, 6) = -64 means that when x increases by 1 unit, keeping y fixed, the value of f(x, y) decreases by 64 units. This indicates that the surface represented by the function f(x, y) is decreasing rapidly in the x-direction at the point (8, 6).
Similarly, the value of fy(8, 6) = -12 means that when y increases by 1 unit, keeping x fixed, the value of f(x, y) decreases by 12 units. This indicates that the surface represented by the function f(x, y) is decreasing less rapidly in the y-direction at the point (8, 6) compared to the x-direction.
Ben O.
thank you04/18/23