To find f(3, y), we need to substitute x = 3 in the expression for f(x, y):
g(y)= f(3, y) = (3)^2 y - 3(3)y^2 = 9y - 9y^2
To find fy(3, y), we need to take the derivative of g(y) with respect to y:
g'(y)= fy(3, y) = (3)^2 - 6(3)y = 9 - 18y
Therefore, the function f(3, y) = 9y - 9y^2 and fy(3, y) = 9 - 18y.