Inactive Tutor answered 04/22/23
a. The point estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments is:
197/378 = 0.5212 (to 4 decimals)
b. At 95% confidence, the margin of error can be calculated using the formula:
margin of error = z* * sqrt(p*(1-p)/n)
where z* is the z-score corresponding to the 95% confidence level, p is the point estimate, and n is the sample size.
Using a table of z-scores or a calculator, we find that the z-score corresponding to the 95% confidence level is 1.96.
Plugging in the values, we get:
margin of error = 1.96 * sqrt(0.5212*(1-0.5212)/378) ≈ 0.0494 (to 4 decimals)
c. The 95% confidence interval estimate can be calculated using the formula:
confidence interval = point estimate ± margin of error
Plugging in the values, we get:
confidence interval = 0.5212 ± 0.0494
The lower bound of the interval is:
0.5212 - 0.0494 = 0.4718
The upper bound of the interval is:
0.5212 + 0.0494 = 0.5706
Therefore, the 95% confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments is (0.4718, 0.5706) (to 4 decimals).