Elements Probability

Question

A simple random sample of 800 elements generates a sample proportion P(line above p)=0.67 .

a. Provide the 99% confidence interval for the population proportion (to 4 decimals).

   ,  

b. Provide the 95% confidence interval for the population proportion (to 4 decimals).

Answer 1

Part A (99% confidence interval)

CI = 0.67 ± 2.807√[(0.67)(1-0.67)/800] ≈ {0.6040,0.7360}

Hence, you would be 99% confident that the true population proportion is contained within the interval {0.6040,0.7360}

Part B (95% confidence interval)

CI = 0.67 ± 1.96√[(0.67)(1-0.67)/800] ≈ {0.6239,0.7161}

Hence, you would be 95% confident that the true population proportion is contained within the interval {0.6239,0.7161}

Hope this helped!