
Zack G. answered 04/11/23
Philosophy Ph.D. with 10 Years of Teaching Experience
Starting with the table, you need to have 3 rows and 3 columns:
K Q #
C
H
#
After setting up the columns and rows, we need to fill in the cells. To do this, you need to consider how many kings are clubs, how many queens are clubs, and how many cards are left when we remove the king and queen of clubs. Do the same thing for hearts. For the last row, you will count up the remaining number of kings, queens, and other cards.
K Q #
C 1 1 11
H 1 1 11
# 2 2 22
We know that we have the correct number of cards because if you sum all of the numbers you will get 52.
Now, you need to go about calculating some probabilities.
To get P(K), add up the king column and divide by the total number of cards (52)
To get P(H), add up the H row and divide by the total number of cards.
For d and e, two events are disjoint when they can never happen at the same time. For d, consider whether or not it is possible to draw a single card that is both a club and a heart. For e, consider whether or not it is possible to draw a card that is both a king and a heart. If it is not possible, then the probability of both events is 0. If it is possible for them to happen at the same time, then use your chart to find where the column and the row intersect. K and H intersect in the table. Take the number in the intersection and divide by the total number of cards.
For the last three problems, use the following formula P(x or y) = P(x) + P(y) - P(x and y). Add up the x's in the table, add up the y's in the table, subtract the intersection of x and y, and divide it all by the number of cards. If x and y are disjoint, then they will not intersect, and so P(x and y) will be 0.
If you have trouble, feel free to ask for more info.

Zack G.
Sure, I'll start with f. P(H or C) is the probability of drawing either a heart or a club. We need to know how many hearts and clubs there are in a deck. Each suit has 13 cards, so the total number of cards that are either a heart or a club is (13 + 13), or 26. So, you have a 26/52 probability of drawing a card that is either a heart or a club. We get the same result by using the formula P(H or C) = P(H) + P(C) - P(H and C). Since P(H and C) is 0 (a card cannot be both a heart and a club), P(H or C) = 13/52 + 13/52 - 0. Now, let's look at an example where the events are not disjoint. P(K or H) is the probability that the card we draw is either a king or a heart. So, count up the kings in the deck and count up the hearts. There are 4 kings out of 52 cards: P(K) = 4/52. There are 13 hearts out of 52 cards: P(H) = 13/52 But, if we just add 4 to 13, we will have double counted the king of hearts. If we count all of the kings and we count all of the hearts we have counted the king of hearts twice. So, we subtract one king of hearts that way we only count him once. P(K or H) = P(K) + P(H) - P(K and H) P(K or H) = 4/52 + 13/52 - 1/52 P(K or H) = 16/5204/12/23
Kayla M.
im confused with the last 3 answers. Also im not sure if I did it correctly. Can you show me and break it down for me please.04/12/23