
William W. answered 04/05/23
Experienced Tutor and Retired Engineer
Yes, the displacement is -4 meters which you found by integrating.
To find the total distance consider that the initial velocity (at t = 0) is -7 m/s and the final velocity (at t = 4) is +5 m/s. So initially, the particle is moving backwards then it turns around and moves forward. That means at some point the velocity is zero. To find that point make 3t - 7 equal to zero:
3t - 7 = 0
3t = 7
t = 7/3
So the total distance is the absolute value of the displacement between t = 0 and t = 7/3 (since thats the part that's negative) added to the distance traveled between t = 7/3 and t = 4. So break the integral into two parts.
If you are doing the integration using a calculator, you can just do 0∫4|3t - 7| dt
You should get 37/3 meters