Edward C. answered 03/25/15
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Caltech Grad for math tutoring: Algebra through Calculus
The formula for exponential decay is
f(t) = A*ek*t where
A = original amount = 200 mg in this case
k = decay constant
t = time = 1590 or 2000 in this case
If the half-life is 1590 then F(1590) = A/2 so
100 = 200*e1590*k
e1590*k = 0.5
ln(e1590*k) = ln(0.5)
1590*k = ln(0.5)
k = ln(0.5) / 1590 = -0.000435941
Now plug t = 2000 into the formula
f(2000) = 200*e(-0.000435941*2000)
= 200*e(-0.871882) = 200*(0.418163823) ~ 83.633 mg