How do I solve this?

Question

If f(5) = 10,

 f ′

 is continuous, and 6

5

f ′(x) dx = 20,

 what is the value of f(6)?

Answer 1

If you evaluate the definite integral you would find an antiderivative of f'(x), which turns out to be f(x).

Then you would evaluate by determining f(6) - f(5). You are given that value as 20, along with the fact that f(5) = 10.

So,

f(6) - f(5) = 20

f(6) - 10 = 20

f(6) = 30