Yefim S. answered 03/31/23
Math Tutor with Experience
x = 60tan(22·2πt/60) = 60tan(11πt/15) ft
x' = 44πsec2(11πt/15) ft/s
θ = 11πt/15 = 30°, x' = 44π ·sec230° = 184.31 ft/s
θ = 11πt/15 = 60°, x' = 44π·sec260° = 552.92 ft/s
θ = 11πt/15 = 85°, x' = 44πsec285° = 18197.45 ft/s