AJ L. answered 03/31/23
Patient and knowledgeable Calculus Tutor committed to student mastery
First, we find possible inflection points by setting f''(x)=0:
f(x) = 6 − x − 8x4
f'(x) = -1 - 32x3
f''(x) = -96x2
0 = -96x2
x = 0
Now we can use the test points x = -1 and x = 1 to observe the function's concavity:
f''(-1) = -96(-1)2 = -96 < 0
f''(1) = -96(1)2 = -96 < 0
Hence, since we can see the function's second derivative is negative for both test points, this means that the open intervals on which the graph of the function is concave downward are (-∞,0)∪(0,∞).
Hope this helped!