Raymond B. answered 03/31/23
Math, microeconomics or criminal justice
r=8
r' =5
A=pir^2=64pi
A' = 2pirr'
= 2pi8(5)= 80pi cm^2 per sec
when r=8, A=64pi
one second later,
when r=8+5=13 and A=pi(13)^2= 169pi, an increase of 169pi-64pi= 105 pi in one sec
when r=3, A =9pi
one second earlier
r=8-5 =3, A = pi(3)^2 = 9pi, from 9pi to 64pi is an increase of 55pi
(55pi+105pi)/2 = 160pi/2 = 80pi cm^2 per second = rate of change of Area when radius =(13+3)/2 = 8