Since f(2) = 11 and f(4) = 27, the points (2,11) and (4,27) are on the line.
Slope = ( 27 - 11) / (4 - 2) = 8
Equation of line: y - 11 = 8(x - 2)
So, y = 8x - 5
Angela L.
asked 03/26/23If f(x) is a linear function, with f(2)=11, and f(4)=27, find an equation for the function in slope-intercept form.
f(x)=
Since f(2) = 11 and f(4) = 27, the points (2,11) and (4,27) are on the line.
Slope = ( 27 - 11) / (4 - 2) = 8
Equation of line: y - 11 = 8(x - 2)
So, y = 8x - 5
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