Solve the integral 2 on top and 1 on the bottom.

Question

²₁∫(x+x^-1)² dx

Answer 1

∫_{(from 1 to 2)} [x² + 2 + x^-2]dx = [(1/3)x³ + 2x -1/x)_{(from 1 to 2)} = (8/3 + 4 -1/2) - (1/3 + 2 - 1)

Simplify.